We know the range of sin(x) is between 1 and 1, inclusively, but that's just with real numbers x. What if our input for the sine function is a complex number? In fact, we can derive the complex definition of sine from the Euler's formula and we can write sin(z) in terms of complex exponential (e^(iz)e^(iz))/(2i) and we will be able to solve sin(z)=2.

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This is my equation of the year in 2017.
To see others, please check out here    • Equation Of The Year!  
#equationoftheyear

ln(2+sqrt(3)),    • small problem that i owe you from sin...  
Euler's formula:    • Euler's Formula (but it's a speedrun)  

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*Sorry I forgot the square root. |z| =sqrt(a^2+b^2)
**Also, I should have written the horizontal axis as "Re" and the vertical axis as "Im"
***The last time I did complex analysis was back in 2012